On the Exponential Diophantine Equation $$(m^2+m+1)^x+m^y=(m+1)^z $$
Author:
Publisher
Springer Science and Business Media LLC
Subject
General Mathematics
Link
https://link.springer.com/content/pdf/10.1007/s00009-020-01613-4.pdf
Reference26 articles.
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2. Bugeaud, Y.: Linear forms in two m-adic logarithms and applications to Diophantine problems. Compos. Math. 132(2), 137–158 (2002)
3. Cao, Z.: A note on the Diophantine equation $$a^x+ b^y = c^z$$. Acta Arith. 91, 85–93 (1999)
4. Fu, R., Yang, H.: On the exponential diophantine equation $$\left( am^{2}+1\right) ^{x}+\left( bm^{2}-1\right) ^{y}=(cm)^{z}$$ with $$c \mid m$$. Period Math Hung. 75, 143–149 (2017)
5. Jeśmanowicz, L.: Some remarks on Pythagorean numbers. Wiadom Mat. 1, 196–202 (1955/1956)
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1. A Note on the Exponential Diophantine Equation $$(rlm^{2}-1)^{x}+(r(r-l)m^{2}+1)^{y}=(rm)^{z}$$;Bulletin of the Brazilian Mathematical Society, New Series;2022-09-30
2. On the Exponential Diophantine Equation $(6m^{2}+1)^{x}+(3m^{2}-1)^{y}=(3m)^{z}$;Fundamental Journal of Mathematics and Applications;2022-06-29
3. On the exponential Diophantine equation mx +(m+1) y =(1+m+m 2) z;Analele Universitatii "Ovidius" Constanta - Seria Matematica;2021-11-01
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