ON THE RECURSIVE SEQUENCE $x_{n+1}=\displaystyle\frac{A}{\prod^k_{i=0}x_{n-i}}+\displaystyle\frac{1}{\prod^{2(k+1)}_{j=k+2}x

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ON THE RECURSIVE SEQUENCE $x_{n+1}=\displaystyle\frac{A}{\prod^k_{i=0}x_{n-i}}+\displaystyle\frac{1}{\prod^{2(k+1)}_{j=k+2}x_{n-j}}$

Published:2003-06-01 Issue:2 Volume:7 Page:
ISSN:1027-5487
Container-title:Taiwanese Journal of Mathematics
language:
Short-container-title:Taiwanese J. Math.

Author:

Stevi´c Stevo

Publisher

The Mathematical Society of the Republic of China

Subject

General Mathematics

Cited by 33 articles. 订阅此论文施引文献订阅此论文施引文献，注册后可以免费订阅5篇论文的施引文献，订阅后可以查看论文全部施引文献

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2. Asymptotic Behavior of Solutions to Difference Equations of Neutral Type;Qualitative Theory of Dynamical Systems;2023-12-27

3. Solvability and representations of the general solutions to some nonlinear difference equations of second order;AIMS Mathematics;2023

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5. On a nonlinear second-order difference equation;Journal of Inequalities and Applications;2022-06-28

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