Bounds on Scott ranks of some polish metric spaces

Author:

Chan William1

Affiliation:

1. Department of Mathematics, University of North Texas, Denton, TX 76203, USA

Abstract

If [Formula: see text] is a proper Polish metric space and [Formula: see text] is any countable dense submetric space of [Formula: see text], then the Scott rank of [Formula: see text] in the natural first-order language of metric spaces is countable and in fact at most [Formula: see text], where [Formula: see text] is the Church–Kleene ordinal of [Formula: see text] (construed as a subset of [Formula: see text]) which is the least ordinal with no presentation on [Formula: see text] computable from [Formula: see text]. If [Formula: see text] is a rigid Polish metric space and [Formula: see text] is any countable dense submetric space, then the Scott rank of [Formula: see text] is countable and in fact less than [Formula: see text].

Funder

NSF

Publisher

World Scientific Pub Co Pte Lt

Subject

Logic

Reference10 articles.

1. Studies in Logic and the Foundations of Mathematics;Ash C. J.,2000

2. Perspectives in Mathematical Logic;Barwise J.,1975

3. London Mathematical Society Lecture Note Serres;Ben Yaacov I.,2008

4. Metric Scott analysis

5. Bounds on continuous Scott rank

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