Abstract
Supposing the phenomena of light to be due to displacements in a rotational ether, we have the following expressions for the kinetic energy and work function in a transparent isotropic medium:- T= ½ ∫ ρ (ξ
2
+ η
2
+ ζ
2
)
d
V, W = ½
c
2
∫ ρμ
2
(
f
2
+
g
2
+
h
2
)
d
V. Here
d
V denotes an element of volume,ρ is the density, ξηζ the displacement, (
fgh
) = 1/ μ
2
curl (ξηζ ),
c
a constant that will prove to be the velocity of light in free ether, whereas μ will be identified with the refractive index. The dynamical equations and boundary conditions are most simply obtained from the Principle of Action, which makes δ ∫ (T - W)
dt
= 0.
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