Abstract
The energies of disintegration of the radioactive atoms, calculated from the alpha ray energies, may be arranged in pairs having sums which are multiples of 3.85. The following table shows this for the disintegration energies of radium C'. The values of the disintegration energies are those given by Rutherford, Lewis, and Bowden and the unit is 10
5
electron volts. Pairs of Disintegration Energies. Multiples of 3.85. 78.29 + 91.12 = 169.41 3.85 x 44 = 169.40 78.29 + 94.93 = 173.22 3.85 x 45 = 173.25 78.29 + 102.69 = 180.98 3.85 x 47 = 180.95 91.12 + 105.26 = 196.38 3.85 x 51 = 196.35 92.41 + 0 = 92.41 3.85 x 24 = 92.40 94.93 + 105.26 = 200.19 3.85 x 52 = 200.20 96.73 + 99.68 = 196.41 3.85 x 51 = 196.35 96.73 + 103·42=200.15 3.85 x 52 = 200.20 100.97 + 107.09 = 208.15 3.85 x 54 = 207.90 102.69 + 105.26 = 207.06 3.85 x 54 = 207.90 The sum of all these pairs is 1825.16, which is equal to 3.8506 x 474. The following table shows the same thing for pairs of disintegration energies of the other radioactive atoms. The values used are those given by Rutherford, Wynn-Williams, Lewis, and Bowden.
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