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2. Anon (n.d.) For the adsorption of any trivalent metal ion where the resin capacity occupied is small D=K.[H+]−3, where K is the adsorption constant. Using the values at 50% adsorption we can substitute for K to yield D=D50.[H+]503.[H+]−3. Therefore the separation factor for two trivalent metal ions may be calculated as the cube of the ratio of their [H+]50 values (note D50, which is only proportional to the aqueous:resin ratio, and [H+] is equivalent for both ions).
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