Abstract
The hexanuclear cluster
complexes Ir2Cu4(C2Ar)8(PPh2R)2
(Ar = Ph, C6H4Me-p, C6H4F-p
or C6F5, R = Ph; Ar = Ph or C6F5,
R = Me) are formed in reactions between IrCl(CO)(PPh2R)2
and CuC2Ar. The rhodium analogues Rh2Cu4(C2Ar)8(PPh2R)2
(Ar = Ph, C6H4Me-p,
C6H4F-p or C6F5; R = Ph or Me) were
obtained with RhC1(CO)(PPh2R)2 or RhC1(PPh3)3
(Ar = C6F5 only).From two of the reactions,
IrCu3(C2Ph3)3 and IrCu(C2C6F5)4/PPh3)3
were also isolated. Further reactions of
the clusters with Fe2(C0)9 have given the octanuclear complexes Ir2Cu4Fe2-(C2Ar)8(C0)8(PPh3)2(Ar=Ph or C6H4Me-p).
Cited by
27 articles.
订阅此论文施引文献
订阅此论文施引文献,注册后可以免费订阅5篇论文的施引文献,订阅后可以查看论文全部施引文献