$$B^0 \rightarrow D^0 \bar{D}^0 K^0$$ B 0 → D 0 D ¯ 0 K 0 , $$B^+ \rightarrow D^0 \bar{D}^0 K^+$$ B + → D 0 D ¯ 0 K + , and the scalar $$D \bar{D}$$ D D ¯ bound state
Author:
Publisher
Springer Science and Business Media LLC
Subject
Physics and Astronomy (miscellaneous),Engineering (miscellaneous)
Link
http://link.springer.com/content/pdf/10.1140/epjc/s10052-016-3946-7.pdf
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