1. So henceforth suppose B(x) 6 = ;. The inequality B(x) 6 = ; implies x 2 T because of the de?nition of T and M . The memberships x;If B(x) = ; then x 2 M : a fortiori x 2 M [ Bj T (t)
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3. B(t) simply dropped. For instance-putting M and T as in Lemma 5-the coherent relation B on X = f1; 2;If x = 2 M then x 2 Bj T (t): the inclusion Bj T (t)