Reaction products of diorganotin(IV) oxides, R2SnO, with nitric acid. Part 1: R = methyl, ethyl, and isopropyl

Abstract

The reaction of diorganotin(IV) oxides, R2SnO with R = Me, Et, and i-Pr, with nitric acid in different stoichiometric ratios resulted in the formation of different products depending on the organic groups. The diorganotin(IV) nitrate hydroxides Me2Sn(NO3)(OH) (1a) Et2Sn(NO3)(OH), α-1b, β-1b, i-Pr2Sn(NO3)(OH) (1c), the diisopropyltin(IV) dinitrate dihydrate, i-Pr2Sn(NO3)2·2H2O (2c) and the diisopropyltin(IV) nitrate oxalate dihydrate, [i-Pr2Sn(NO3)]2Ox·2H2O (3) as side-product. On examination of the solubility of the primary reaction products in different solvents, the two additional compounds Me2Sn(NO3)(OH)·DMSO (4) and 2i-Pr2Sn(NO3)2·3DMSO = [i-Pr2Sn(NO3)(dmso)3] [i-Pr2Sn(NO3)3] (5) have been isolated. All compounds have been structurally characterized by single crystal X-ray diffraction with special respect to dimensionality (1a, α-1b, 1c = dimeric molecules hydrogen bonded to one-dimensional chains; β-1b = two-dimensional coordination polymer; 2c = monomeric; 3 = monomeric, tin atoms linked via a double side-on chelating oxalate ion; 4 = dimeric, 5 = monomeric anion/cation), tin coordination (trigonal-bipyramidal = 1a, α-1b, 1c; six-fold = β-1b; seven-fold = 3, 4, 5-cation; eight-fold = 2c, 5-anion) and nitrate bonding modes (monodentate = 1a, α-1b, 1c; unsymmetrical bidentate = 3, symmetrical bidentate = 3, 4, 5-cation, 5-anion; syn-anti bridging = β-1b), the latter one being analysed using both, Sn–O and N–O distances.