Solution of the conjecture: If <mml:math altimg="si23.gif" overflow="scroll" xmlns:xocs="http://www.elsevier.com/xml/xocs/dtd" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://www.elsevier.com/xml/ja/dtd" xmlns:ja="http://www.elsevier.com/xml/ja/dtd" xmlns:mml="http://www.w3.org/1998/Math/MathML" xmlns:tb="http://www.elsevier.com/xml/common/table/dtd" xmlns:sb="http://www.elsevier.com/xml/common/struct-bib/dtd" xmlns:ce="http://www.elsevier.com/xml/common/dtd" xmlns:xlink="http://www.w3.org/1999/xlink" xmlns:cals="http://www.elsevier.com/xml/common/cals/dtd"><mml:mi>n</mml:mi><mml:mo>≡</mml:mo><mml:mn>0</mml:mn><mml:mo stretchy="false">(</mml:mo><mml:mi>mod</mml:mi><mml:mspace width="0.16em"/><mml:mn>4</mml:mn><mml:mo stretchy="false">)</mml:mo></mml:math>, <mml:math altimg="si24.gif" overflow="scroll" xmlns:xocs="http://www.elsevier.com/xml/xocs/dtd" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://www.elsevier.com/xml/ja/dtd" xmlns:ja="http://www.elsevier.com/xml/ja/dtd" xmlns:mml="http://www.w3.org/1998/Math/MathML" xmlns:tb="http://www.elsevier.com/xml/common/table/dtd" xmlns:sb="http://www.elsevier.com/xml/common/struct-bib/dtd" xmlns:ce="http://www.elsevier.com/xml/common/dtd" xmlns:xlink="http://www.w3.org/1999/xlink" xmlns:cals="http://www.elsevier.com/xml/common/cals/dtd"><mml:mi>n</mml:mi><mml:mo>></mml:mo><mml:mn>4</mml:mn></mml:math>, then <mml:math altimg="si25.gif" overflow="scroll" xmlns:xocs="http://www.elsevier.com/xml/xocs/dtd" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://www.elsevier.com/xml/ja/dtd" xmlns:ja="http://www.elsevier.com/xml/ja/dtd" xmlns:mml="http://www.w3.org/1998/Math/MathML" xmlns:tb="http://www.elsevier.com/xml/common/table/dtd" xmlns:sb="http://www.elsevier.com/xml/common/struct-bib/dtd" xmlns:ce="http://www.elsevier.com/xml/common/dtd" xmlns:xlink="http://www.w3.org/1999/xlink" xmlns:cals="http://www.elsevier.com/xml/common/cals/dtd"><mml:msub><mml:mrow><mml:mi>K</mml:mi></mml:mrow><mml:mrow><mml:mi>n</mml:mi></mml:mrow></mml:msub></mml:math> has a super vertex-magic total labeling-Reference-Cited by-同舟云学术

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Solution of the conjecture: If n≡0(mod4), n>4, then Kn has a super vertex-magic total labeling

Published:2007-10 Issue:21 Volume:307 Page:2525-2534
ISSN:0012-365X
Container-title:Discrete Mathematics
language:en
Short-container-title:Discrete Mathematics

Author:

Gómez J.

Publisher

Elsevier BV

Subject

Discrete Mathematics and Combinatorics,Theoretical Computer Science

Reference12 articles.

1. On the degrees of a strongly vertex-magic graph;Balbuena;Discrete Math.,2006

2. Balanced magic rectangles;Bier;European J. Combin.,1993

3. A dynamic survey of graph labeling;Gallian;Eletron. J. Combin.,2005

4. J. Gómez, Two new methods to obtain super vertex-magic total labelings of graphs, Discrete Math., submitted for publication.

5. On vertex-magic total labelings of complete graphs;Gray;Bull. Inst. Combin. Appl.,2003

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1. Flower snark and related graph’s reverse super edge – Magic labelings;RECENT TRENDS IN PURE AND APPLIED MATHEMATICS;2019

2. Vertex-Magic Total Labelings;Magic and Antimagic Graphs;2019

3. Solution to some open problems on E -super vertex magic labeling of disconnected graphs;Applied Mathematics and Computation;2015-10

4. E-Super Vertex Magic Regular Graphs of Odd Degree;Electronic Notes in Discrete Mathematics;2015-07

5. Edge-Magic Total Labelings;Magic Graphs;2012-09-28

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